If in a system the force of attraction between two point masses of `1kg` each situated `1km` apart is taken as a unit force and is called newton(newton written in reverse order) If `G = 6.67 xx 10^(-11) N-m^(2)kg^(-2)` in `\SI` units, the relation of newton and newton is

Options

A. 1 notwen`=6.67xx10^(-11)` newton
B. 2 notwen`=6.67xx10^(-17)` newton
C. 3 notwen`=6.67xx10^(-17)` newton
D. 4 notwen`=6.67xx10^(-12)` newton

Answer

C

Explanation

`1` netwen `=G (1 kgxx1 kg)/((1 km)^(2))=((6.67xx10^(-11))/(10^(6)))((kg^(2))/m^(2))`
`=6.67xx10^(-17)` newton