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The line of action of a force vec(F)=(-3...

The line of action of a force `vec(F)=(-3hat(i)+hat(j)+5hat(k)) N` passes through a point `(7, 3, 1)`. The moment of force `(vec(tau)=vec(r)xxvec(F))` about origin is given by

A

`14hat(i)+38hat(j)+16hat(k)`

B

`14hat(i)+38hat(j)-16hat(k)`

C

`14hat(i)-38hat(j)+16hat(k)`

D

`14hat(i)-38hat(j)-16hat(k)`

Text Solution

Verified by Experts

The correct Answer is:
C
`vec(tau)=vec(r)xxvec(F)=|(hati,hatj,hatk),(7,3,1),(-3,1,5)|=14hat(i)-38hat(j)+16hat(k)`
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