The magnitude of scalar product of two vectors is `8` and of vector product is `8sqrt(3)`. The angle between them is:

Options

A. `30^(@)`
B. `60^(@)`
C. `120^(@)`
D. `150^(@)`

Answer

B, C

Explanation

`|vec(A).vec(B)|=AB|cos theta|=8`,
`|vec(A)xxvec(B)|=AB|sin theta|=8 sqrt(3)`
`rArr |tan theta|=(8sqrt(3))/8=sqrt(3) rArr theta=60^(@), 120^(@)`