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Path traced by a moving particle in spac...

Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves `[y=f(x)]` is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor.
In above the velocity `(i.e. (dvec(r))/(dt))` at `t=0` is :-

A

`2bhat(j)`

B

`ahat(i)`

C

`(a-2b)hat(i)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`(dvec(r))/(dt)=ahat(i)-2bt hat(j)` at `t=0, (dvec(r))/(dt)=ahat(i)`
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Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. In above question initial acceleration (i.e. (d^(2)vec(r))/(dt^(2))) of particle is :-

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