A vector `vecA` of length 10 units makes an angle of `60^(@)` with the vector `vecB` of length 6 units . Find the magnitude of the vector difference `vecA-vecB` & the angle it makes with vector `vecA`.

Answer

`2sqrt(19), tan^(-1) ((3sqrt(3))/7)`

Explanation

`|vec(A)-vec(B)|=sqrt(A^(2)+B^(2)-2AB cos theta)`
`=sqrt((10)^(2)+(6)^(2)-2(10)(6)cos 60^(@))=2sqrt(19)`
`tan alpha=(6 sin 60^(@))/(10-6 cos 60^(@))=(6xxsqrt(3)//2)/(10-3)=(3sqrt(3))/7`
`rArr alpha=tan^(-1) ((3sqrt(3))/7)`