Acceleration of particle moving in straight line can be written as `a=(dv)/(dt)=v(dv)/(dx)`. From the given graph find acceleration at `x=20 m`.

Answer

`100 m//s^(2)`

Explanation

From graph `(dv)/(dx)=(90-50)/(40-20)=40/20(dv)/(dx)=2`
`("at " x=20)=50 m//s`
`a=v(dv)/(dx) rArr a=50xx2=100 m//s^(2)`