Home
Class 11
PHYSICS
The position vector of a particle is giv...

The position vector of a particle is given by `vec(r)=1.2 t hat(i)+0.9 t^(2) hat(j)-0.6(t^(3)-1)hat(k)` where t is the time in seconds from the start of motion and where `vec(r)` is expressed in meters. For the condition when `t=4` second, determine the power `(P=vec(F).vec(v))` in watts produced by the force `vec(F)=(60hat(i)-25hat(j)-40hat(k)) N` which is acting on the particle.

Text Solution

Verified by Experts

The correct Answer is:
1044

`vec(v)=(dvec(r))/(dt)=1.2 hat(i)+1.8that(j)-1.8t^(2)hat(k)`
at `t=4s, vec(v)=1.2 hat(i)+7.2 hat(j)-28.8 hat(k)`
`P=vec(F).vec(v)=(60hat(i)-25hat(j)-40hat(k)).(1.2hat(i)+7.2hat(j)-28.8hat(k))`
`=1044W`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN |Exercise EXERCISE-5(A)|15 Videos
  • MISCELLANEOUS

    ALLEN |Exercise Exersice -05(B)|20 Videos
  • MISCELLANEOUS

    ALLEN |Exercise Exercise-04 [A]|28 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-7|8 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-IV|7 Videos

Similar Questions

Explore conceptually related problems

The position of a particle is given by vec r= 3.0 t hat i - 2.0 t^2 hat j + 4.0 hat k m , wher (t) in seconds and the coefficients have the proper units for vec r to be in metres. Find the vec v and vec a of the particle ?

The position of a particle is given by vec r= 3.0 t hat i - 2.0 t^2 hat j + 4.0 hat k m , wher (t) in seconds and the coefficients have the proper units for vec r to be in metres. what is the magnitude of the velocity of particle at t=2 sec ?

Position vector of a particle is expressed as function of time by equation vec(r)=2t^(2)+(3t-1) hat(j) +5hat(k) . Where r is in meters and t is in seconds. Find the velocity vector

The position vector of a particle is determined by the expression vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k . The displacement traversed in first 10 seconds is :

The motion of a particle is defined by the position vector vec(r)=(cost)hat(i)+(sin t)hat(j) Where t is expressed in seconds. Determine the value of t for which positions vectors and velocity vector are perpendicular.

Position vector vec(r) of a particle varies with time t accordin to the law vec(r)=(1/2 t^(2))hat(i)-(4/3t^(1.5))hat(j)+(2t)hat(k) , where r is in meters and t is in seconds. Find suitable expression for its velocity and acceleration as function of time.

Position vector vec(r) of a particle varies with time t accordin to the law vec(r)=(1/2 t^(2))hat(i)-(4/3t^(3))hat(j)+(2t)hat(k) , where r is in meters and t is in seconds. Find suitable expression for its velocity and acceleration as function of time

The position vector of a particle of mass m= 6kg is given as vec(r)=[(3t^(2)-6t) hat(i)+(-4t^(3)) hat(j)] m . Find: (i) The force (vec(F)=mvec(a)) acting on the particle. (ii) The torque (vec(tau)=vec(r)xxvec(F)) with respect to the origin, acting on the particle. (iii) The momentum (vec(p)=mvec(v)) of the particle. (iv) The angular momentum (vec(L)=vec(r)xxvec(p)) of the particle with respect to the origin.

If vec(A) =2hat(i)-2hat(j) and vec(B)=2hat(k) then vec(A).vec(B) ……

Find the angle between vec(P) = - 2hat(i) +3 hat(j) +hat(k) and vec(Q) = hat(i) +2hat(j) - 4hat(k)