Using mass (M), length (L) time (T) and current (A) as fundamental quantities, the dimensions of permeability are:

Options

A. `ML^(-2)T^(2)A`
B. `M^(-1)L^(-3)T^(4)A^(2)`
C. `MLT^(-2)A`
D. `ML^(2)T^(-1)A^(2)`

Answer

B

Explanation

`[in_(0)]=([Q^(2)])/([F][4pi][sigma^(2)])=(A^(2)T^(2))/(MLT^(-2)xxL^(2))=M^(-1)L^(-3)T^(4)A^(2)`