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An electron of mass m(e ) initially at r...

An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal to

A

`1`

B

`(m_(p)//m_(e))^(1//2)`

C

`(m_(e)//m_(p))^(1//2)`

D

`1836`

Text Solution

Verified by Experts

The correct Answer is:
B

`t=sqrt((2x)/a)=sqrt((2x xx m)/(qE)) :. T prop sqrt(m/q) prop sqrt(m)`
[when x, q & E are same] `:. T_(2)/t_(1)=sqrt(m_(p)/m_(e))`
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