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When two concentric shells are connected...

When two concentric shells are connected by a thin conducting wire, whole of the charge of inner shell transfers to the outer shell and potential difference between them becomes zero. Surface charge densities of two thin concentric spherical shells are `sigma` and `-sigma` respectively. Their radii are R and `2R`. Now they are connected by a thin wire.

Suppose electric field at a distance `r=(3R)/2` was `E_(1)` before connecting the two shells and `E_(2)` after connecting the two shells, then `|E_(2)/E_(1)|` is :-

A

zero

B

1

C

`9//8`

D

`8//9`

Text Solution

Verified by Experts

The correct Answer is:
A
Electric field at `r=(3R)/2` [Before connecting]
`x=(3R)/2`
`E_(1)=1/(4pi in_(0))xx(sigma4piR^(2))/((3R)/2)^(2)+0`
After connecting `E_(2)=0`
Hence `|E_(2)/E_(1)|=0`
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