Home
Class 12
PHYSICS
At time t=0 s a car passes a point with ...

At time `t=0` s a car passes a point with velocity of `16 m//s` and thereafter slows down with acceleration `a=-0.5t m//s^(2)` ,where `t` is in seconds. It stops at the instant `t=`

A

`32 s`

B

`16 s`

C

`8.0 s`

D

`4.0 s`

Text Solution

Verified by Experts

The correct Answer is:
C
`a-t` graph

Area `=(-t^(2))/(4)=` change in velocity
`rArr` Final velocity `=16-(t^(2))/(4)=0`
`rArr t=8 sec.`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A particle moves on x-axis with a velocity which depends on time as per equation v=t^(2)-8t+15(m//s) where time t is in seconds. Match the columns.

If v=(t^(2)-4t+10^(5)) m/s where t is in second. Find acceleration at t=1 sec.

A particle is moving along a straight line along x-zxis with an initial velocity of 2 m//s towards positive x-axis. A constant acceleration of 0.5 m//s^(2) towards negative x-axis starts acting on particle at t=0 . Find velocity (in m//s ) of particle at t=2 s .

A particle is moving along a straight line along x-zxis with an initial velocity of 4 m//s towards positive x-axis. A constant acceleration of 1 m//s^(2) towards negative x-axis starts acting on particle at t=0 . Find velocity (in m//s ) of particle at t=2 s .

A particle moving in a straight line has its velocit varying with time according to relation v = t^(2) - 6t +8 (m//s) where t is in seconds. The CORRECT statement(s) about motion of this particle is/are:-

When a 2 kg car driven at 20 m//s on a level road is suddenly put into netural gear (i.e. allowed to coast), the velocity decreases in the following manner: V=20/(1+(t/20))m//s Where t is time in sec. The deceleration of car at the instant its speed is 10 m//s is.

The velocity of a particle is given by v=(5t^(2)-6t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.

The velocity of a particle is given by v=(5t^(2)-2t+9)m//s where t is time in seconds. Find its acceleration at t=4 second.

The velocity of a particle is given by v=(4t^(2)-4t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.