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A block of mass "5kg" is placed on a rou...

A block of mass "`5kg`" is placed on a rough horizontal surface . A veriable force of `5t` Newton acts on it horizontally . If block starts slipping at `t=4 sec` and its acceletation at `t=5 sec` is `2 m//s^(2)`.Find the value of `10(mu_(s)-mu_(k))`.

A

`1`

B

`2`

C

`3`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
A
`mu_(5)5g=5xx4rArrmu_(5)=.4`
and `25-mu_(k)5g=5xx2rArrmu_(k)=0.3`
`10(.4-.3)=1`
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