The amount of heat released when `20 ml`,`0.5 M` `NaOH`is mixed with `100 ml`,`0.1 M` `H_(2)SO_(4)` is `xKJ`. The heat of neutralization will be `:-`

Options

A. `-100x(KJ)/(mol)`
B. `+50x(KJ)/(mol)`
C. `-200x(KJ)/(mol)`
D. `-50x(KJ)/(mol)`

Answer

A

Explanation

`N//A`