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A stone is thrown at an angle theta to t...

A stone is thrown at an angle `theta` to the horizontal reaches a maximum height H. Then the time of flight of stone will be:

A

`sqrt((2H)/(g))`

B

`2sqrt((2H)/(g))`

C

`2sqrt((2Hsintheta)/(g))`

D

`sqrt((2Hsintheta)/(g))`

Text Solution

Verified by Experts

The correct Answer is:
B
By using `s=vt-(1)/(2)at^(2)` , we get
`H=0-1/2(-g)((T)/(2))^(2)rArrT=2sqrt((2H)/(s))`
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