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A particle of mass 5kg moving in the X-Y...

A particle of mass `5kg` moving in the `X-Y` plane has its potential energy given by `U=(-7x+24y) J`. The particle is initially at origin and has a velocity `vec(U)=(14.4+4.2J)m//s`

A

The particle has speed `20 m//s` at `t=4` sec

B

The particle has an acceleration `5 m//s^(2)`

C

The acceleration of particle is normal to its intial velocity.

D

None of the above each correct

Text Solution

Verified by Experts

The correct Answer is:
C

Force acting on the particle
`vec(F)=-(delU)/(delx)hat(i)-(delU)/(dely)hat(j)=7hat(i)-24hat(j)`
Accerleration of particle
`=(F)/(m)=sqrt(7^(2)+24^(2))/(5)=(25)/(5)=5ms^(-2)`
velocity of particle
`vec(v)=vec(u)+vec(a)t=(14.4hat(i)+4.2hat(j))+(1.4hat(i)-4.8hat(j))t`
Speed at `4` sec`=sqrt((14.4+5.6)^(2)+(19.2-4.2)^(2))`
`=25ms^(-1)`
Now `vec(a).vec(u)=(1.4hat(i)-4.8hat(j)).(14.4hat(i)+4.2hat(j))=20.16-20.16=0rArr` The acceleration of particle is normal to its initial velocity.
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