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Two bars of masses m(1) and m(2) connect...

Two bars of masses `m_(1)` and `m_(2)` connected by a non`-`deformed light spring rest on a horizontal plane. The coefficient of friction between the bars and the surface is equal to `mu`. What minimum constant force has to be appled in the horizontal direction to the bar of mass `m_(1)` in order to shift the other bar?

A

`(m_(1)+m_(2)/(2))mug`

B

`(m_(2)+m_(1)/(2))mug`

C

`(m_(1)-m_(2)/(2))mug`

D

`(2m_(2)+m_(1)/(2))mug`

Text Solution

Verified by Experts

The correct Answer is:
A

Let force constant of spring is `k` then `mum_(2)g=kx` & `Fx-mum_(1)g-(1)/(2)kx^(2)=0`
`rArrF=(m_(1)+(m_(2))/(2))mug`
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