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The position of a particle moving in spa...

The position of a particle moving in space varies with time `t` according as `:-`
`x(t)=3 cosomegat`
`y(t)=3sinomegat`
`z(t)=3t-8`
where `omega` is a constant. Minimum distance of particle from origin is `:-`

A

`1` unit

B

`2` unit

C

`3` unit

D

`4` unit

Text Solution

Verified by Experts

The correct Answer is:
C

Distance from origin, `r=sqrt(x^(2)+y^(2)+z^(2))`
`=sqrt(9cos^(2)omegat+9sin^(2)omegat+(4t-8)^(2)`
`=sqrt(9+(4t-8)^(2)`
For minimum `t,4t-8=0rArr1=2` unit
`rArrr_(min)=3units`
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