If momentum `(P)`, area `(A)` and time `(T)` are taken to be fundamental quntities, then power has the dimensional formula.

Options

A. `(P^(1)A^(-1)T^(1))`
B. `(P^(2)A^(1)T^(1))`
C. `(P^(1)A^(-1//2)T^(1))`
D. `(P^(1)A^(1//2)T^(-2))`

Answer

D

Explanation

[Power]=[(work)/(time)]`=`[(forcexxlength)/(time)]
`=[(momentumxxsqrtarea)/(time)^(2)]=[P^(1)A^(1//2)T^(-2)]`