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Figure shows an At wood machine in which...

Figure shows an At wood machine in which `m_(1)+m_(2)=M` is constant. Now a mass `Deltam` is transferred from `m_(2)` to `m_(1)`. Now a graph of `(a)/(g)` vs `Deltam` is plotted. Mark the most appropriate option (here `m_(1)gtm_(2)`) `:-`

A

B

C

D

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Verified by Experts

The correct Answer is:
A

Ans.(1)
`a=((m_(1)-m_(2)))/(m_(1)+m_(2))grArr (a)/(g)=(m_(1)-m_(2))/(M)`
Here `m_(2)darr` and `m_(1)uarr` so `(a)/(g) uarr`
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