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Consider the equation d/(dt)(int vec(F)....

Consider the equation `d/(dt)(int vec(F). dvec(S))=A(vec(F).vec(p))` where `vec(F) equiv` force, `vec(s) equiv` displacement, t `equiv` time and `vec(p)`= momentum. The dimensional formula of A will be

A

`M^(0)L^(0)T^(0)`

B

`ML^(0)T^(0)`

C

`M^(-1)L^(0)T^(0)`

D

`M^(0)L^(0)T^(-1)`

Text Solution

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The correct Answer is:
C
`[(d)/(dt)(intvec(F).dvec(S))]=[A(vec(F).vec(p))]`
`rArr[(F_(s))/(1)]=[AFp]rArr[A]rArr[(s)/(pt)]=(L)/(MLT^(-1)xxT)=M^(-1)`
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