If the center of mass of a system of three particles of masses `1kg,2kg,3kg` is at the point `(1m,2m,3m)` and center of mass of another group of two partices of masses `2kg` and `3kg` is at point `(-1m,3m,-2m)`. Where a `5kg` particle should be placed, so that center of mass of the system of all these six particles shifts to the center of mass of the first system?

Options

A. (a)`(1m,-3m,2m)`
B. (b)`(3m,3m,2m)`
C. (c)`(-1m,2m,3m)`
D. (d)`(3m,1m,8m)`

Answer

D

Explanation

Ans.(4)
`(6(hat(i)+2hat(j)+3hat(k))+5(-hat(i)+3hat(j)-2hat(k))+5vec(r))/(16)=(hati+2hatj+3hat(k))`
`vec(r)=(3hat(i)+hat(j)+8hat(k))`