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underset(("Lewis base"))(B(2)H(6)+2Lrarr...

`underset(("Lewis base"))(B_(2)H_(6)+2Lrarr2BH_(3)L)`
`L` would be `:`

A

`NH_(3)`

B

`CH_(3)NH_(2)`

C

`(CH_(3))_(2)NH`

D

`(CH_(3))_(3)N`

Text Solution

Verified by Experts

The correct Answer is:
D
`N//A`
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