`4` gm `NaOH` is dissolved in `1` litre solution containing `1` mole `CH_(3)COOH` and `1` mole `CH_(3)COONa`. Calculate pH of resulant solution.
(`K_(a)` of `CH_(3)COOH=1.8xx10^(-5)`, `log11=1.04`)

Options

A. `4.70`
B. `4.83`
C. `5.92`
D. `6.87`

Answer

B

Explanation

`pH=pKa+log["Salt"]/[["Acid"]]=4.74+log[1.1]/[[0.9]]`
Reaction :
`CH_(3)COOH+NaOHrarrCH_(3)COOHNa`
`{:(1," ",0.1," ",1),(1-0.1," ",0," ",1.1):}`