Equilibrium constant for the following reactions have been determined at `823K`.
`CaO(s)+H_(2)(g)hArrCO(s)+H_(2)O(g) K_(1)=60`
`CaO(s)+CO(g)hArrCO(S)+CO_(2)(g) K_(2)=400`
Using this information, calculate, equilibrium constant (at the same temperature) for `:-` `CO_(2)(g)+H_(2)(g)hArrCO(s)+H_(2)O(g)K_(3)=?`
`CO(g)+H_(2)O(g)hArrCO_(2)(g)+H_(2)(g)K_(4)=?`

Options

A. `K_(3)=0.15,K_(4)=6.66`
B. `K_(3)=1.5,K_(4)=66.6`
C. `K_(3)=15,K_(4)=666`
D. None

Answer

A

Explanation

`K_(3)=(K_(1))/(K_(2))`
`K_(4)=(K_(2))/(K_(1))`