Two cars a and B starts motion with a velocity of `10 m//s` and `20 m//s` respectively. Car a moves with a constant acceleration of `2.5 m//s^(2)` and car B have constant acceleration of `0.5 m//s^(2)` as shown in figure. Find when car A will over take car B. Dimension of car is negligible as compare to distance. Find the time after which car A over takes car B.

Explanation

`s_("rev")=u_("rev")t+1/2 a_("rev")t^(2)`
`0=-10t+t^(2)`
`t=0, t=10` sec
`t=10` sec