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A particle is dropped from the top of a high building 360 m. The distance travelled by the particle in ninth second is `(g=10 m//s^(2))`

A

85 m

B

60 m

C

40 m

D

can't be determined

Text Solution

Verified by Experts

The correct Answer is:
C
Total time taken by particle to reach the ground `T=sqrt((2H)/g)=sqrt((2xx360)/10)=6sqrt(2)=8.484 s`
Distance travelled in 8 seconds `=1/2 g t^(2)=1/2 (10)(8)^(2)=320 m`
Therefore distance travelled in ninth second `=360-320=40 m`
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