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The trajectory of a projectile in a vert...

The trajectory of a projectile in a vertical plane is `y=sqrt(3)x-2x^(2)`. `[g=10 m//s^(2)]`

Range OA is :-

A

`sqrt(3)/2`

B

`sqrt(3)/4`

C

`sqrt(3)`

D

`3/8`

Text Solution

Verified by Experts

The correct Answer is:
A
Range of A `=(u^(2) sin2theta)/g=(10xxsin 120^(@))/10=sqrt(3)/2`
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