A ball whose kinetic energy is `E` , is projected at an angle of `45^(@)` to the horizontal . The kinetic energy of the ball at the highest point of its flight will be

Options

A. E
B. `E//sqrt(2)`
C. `E//2`
D. zero

Answer

3

Explanation

Kinetic energy of a projectile at the highest point `=E cos^(2) (theta)` where E is the kinetic energy of projection, `theta` is the angle of projection.
`E_("highest point")=E(cos 45^(@))^(2)=E(1/sqrt(2))^(2)=E/2`