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A particle is projected at 60(@) to the...

A particle is projected at ` 60(@)` to the horizontal with a kinetic energy `K` . The kinetic energy at the highest point is

A

K

B

zero

C

`K//4`

D

`K//2`

Text Solution

Verified by Experts

The correct Answer is:
3
`K_("highest point")=[K_("Point of projection")] cos^(2) theta`
`K_(H)=K(cos 60^(@))rArr K_(H)=K/4`
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