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A water fountain on the ground sprinkles...

A water fountain on the ground sprinkles water all around it . If the speed of water coming out of the fountain is ` v` , the total area around the fountain that gets wet is :

A

`pi/2 v^(4)/g^(2)`

B

`pi v^(2)/g^(2)`

C

`pi v^(2)/g`

D

`pi v^(4)/g^(2)`

Text Solution

Verified by Experts

The correct Answer is:
4
`R_("max")=u^(2)/g`, Area `=pir^(2)=(piu^(2)R_("max")^(2))/g^(2)`
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