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0.2004 g of glucose gave on combustion 0...

0.2004 g of glucose gave on combustion 0.2940 g of `CO_(2)` and 0.1202 g of `H_(2)O`. Find the percentage composition.

A

`C_(4)H_(5)`

B

`C_(2)H_(6)`

C

`C_(4)H_(8)`

D

`C_(4)H_(10)`

Text Solution

Verified by Experts

The correct Answer is:
B
for unknown hydrocarbon
` C_(X)H_(Y)+(X+(Y)/(4))O_(2)toCO_(2)+(Y)/(2)H_(2)O`
`{:(1mL,,,xmL,(y)/(2)mL),(10mL,,,10xmL,10(y)/(2)mL):}`
10ml = 20 and` 10 (Y)/(2) = 30` Hence formula is `C_(2)H_(6)`
X =2 Y = 6
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