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Equal masses of H(20),N(20) and methane ...

Equal masses of `H_(20),N_(20)` and methane taken in a container of volume V at temperature `27^(@)C` in identical cnditions. The ratio of volumes of gases `H_(2):N_(2):` methane would be :-

A

`56:4:7`

B

`7:04:56 ` AM

C

`2:28:16` AM

D

`8:14:01` AM

Text Solution

Verified by Experts

The correct Answer is:
A
Let the mass be 100 gm
Ratio of moles = Ratio of volumes
`=(100)/(2):(100)/(28)=(100)/(16)`
`= 56 : 4 : 7`
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