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500 ml of a gaseous hydrocarbon when bur...

500 ml of a gaseous hydrocarbon when burnt in excess of `O_(2)` gave 2.0litres of `CO_(2)` and 2.5 litres of water vapours under same conditions. molecular formula of the hydrocarbon is:-

A

`C_(4)H_(8)`

B

`C_(4)H_(10)`

C

`C_(5)H_(10)`

D

`C_(5)H_(12)`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(C_(x)H_(y)+(x+(y)/(4))O_(2),to,xCO_(2)+,(y)/(2)H_(2)O,),(1mL,,2mL,(y)/(2)mL,),(500mL,,500mL,250ymL,),("Hence,and",,,,),(500x=2000,,250y,=2500mL,),(x=4,,y=10mL,,),(":. formula = C_(4)H_(10),,,,):}`
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