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By dissociation of 4g mol of of PCI(5) p...

By dissociation of 4g mol of of` PCI_(5)` produce 0.8 mol of `PCI_(3)` if vol of container is 1 ltr the equilibrium constant :-

A

0.2

B

0.1

C

0.4

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(PCl_(5),rarr,PCl_(3)+,Cl_(2)),(4,,0,0),(4-0.8,,0.8,0.8):}`
` K_(c)= (0.8xx0.8)/(3.2)=0.2`
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