Given the reaction` b//w` 3 gases represented `X_(2),Y_(2),Z_(2) ` to give the compound `XYZ_(g)`
`X_(2(g))+Y_(2(g))+Z_(2(g)) hArr 2_(g)`
At equilibrium `conc^(n)`
of `X_(2)=3M,Y_(2)=6M,Z_(2)`=9M
`XYZ=6M`
If the reaction take place in a sealed vessel at `527^(@)C`, then the value of `K_(C)` will be :-

Options

A. `(27)/(2)`
B. `(2)/(9)`
C. 36
D. 24

Answer

B

Explanation

`K_(C)=(6)^(2)/(3xx6xx9)=(2)/(9)`