The Ksp of `Ag _(2)CrO_(4)` is ` 1.1xx10^(-12)` at 298 K, solubility in `(mol//L)` of `Ag_(2)CrO_(4)` in `0.1 M AgNO_(3)` solution is :-

Options

A. `1.1xx10^(-11)`
B. `1.1xx10^(-10)`
C. `1.1xx10^(-12)`
D. `1.1xx10^(-9)`

Answer

B

Explanation

`{:(A_(g_(2))CrO_(4),hArr,2Ag^(+),+,CrO_(4)^(-2),),(,,(25+0.1) s^('),,):}`
`{:(AgNO_(3),to,Ag^(+),+,NO_(3),),(,,0.1+25^('),0.1,):}`
`Ksp=[0.1+25^(')][s^(')]`
`s^(')=1.1xx10^(-10) ("mole//litre")`