Solubility product of `BaCl_(2)` is `4xx10^(-9)`. Its solubility in moles//litre would be

Options

A. `4xx10^(-3)`
B. `3.2xx10^(-9)`
C. `10^(-3)`
D. `1xx10^(-9)`

Answer

C

Explanation

`KsP=45^(3)=4xx10^(-9)rArr5=10^(-3)`