solubility product of radium sulphate is `4xx10^(-1)`. What will be the solubility of` Ra^(2+)` in` 0.10 M NaSO_(4)` ?

Options

A. `4xx10^(-10)` M
B. `2xx10^(-5)M`
C. `4xx10^(-5)M`
D. `2xx10^(-10)M`

Answer

A

Explanation

`{:(RaSO_(4),hArr,Ra^(+2),+SO_(4)^(-2),),(,,,,),(Na_(2)SO_(4),to,2Na^(+),+SO_(4)^(-2),),(,,0.20,0.10+5,),(Ksp=[5^(')],,[5^(')+0.10],,),(s^(')=4xx10^(-10),,,,):}`