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What is the [OH^(-)] in the final soluti...

What is the `[OH^(-)]` in the final solution prepared by mixing `20.0 mL` of `0.050 M HCl` with `30.0 mL` of `0.10 M Ba(OH)_(2)`?

A

0.10M

B

0.40M

C

0.0050M

D

0.12M

Text Solution

Verified by Experts

The correct Answer is:
A
meq. Of HCI `= 0.050xx 20=1`
meq. Of Ba `(OH)_(2)=0.10xx2xx30=6`
total volume `= 20+30=50ml`
`[OH^(-)]=(5)/(50)=0.1`
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