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What will be the degree of dissociation ...

What will be the degree of dissociation of 0.005M `NH_(4)OH`solution. If `pK_(b)` for `NH_(4)OH` is 4.7

A

`2%`

B

`0.03%`

C

`1.4%`

D

`6. 32%`

Text Solution

Verified by Experts

The correct Answer is:
D
`pK_(b)=4.2`
`K_(b)=10^(-5)xx10^(0.3)`
`K_(b)=2xx10^(-5)=Calpha^(2)`
`2xx10^(-5)=5xx10^(-3) a^(2)`
`alpha^(2)=(2xx10^(-5))/(5xx10^(-3))=0.4xx10^(-2)`
`alpha^(2)=6.32xx10^(-2)xx100=6.32%`
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