The solubility of `PbF_(2)` (formula mass =245) is 0.46 g/L. What is the solubility product?

Options

A. `1.1xx10^(-10)`
B. `2.6xx10^(-8)`
C. `1.1xx10^(-7)`
D. `16.8xx10^(-9)`

Answer

B

Explanation

`S=(0.46)/(245)=187xx10^(-3)M`
`Ksp=4S^(3)`
`=4xx(187xx10^(-3))^(3)`
`Ksp=2.6xx10^(-8)`