The heat of neutralization of LiOH and `H_(2)SO_(4)` at `25^(@)`C is `69.6 KJ mol^(-1)`. Calculate the heat of innisation of LiOH will be nearly :-

Options

A. `22.5KJmol^(-1)`.
B. `90 KJ mol^(-1)`.
C. `45KJ mol^(-1)`
D. `33.6KJmol^(-1)`

Answer

A

Explanation

`2LiOH+H_(2)SO4toLi_(2)SO_(2)+2H_(2)SO_(4)O`
`Delta H_"(neut.)"=-69.6KJ//mol=2DeltaH_(ion)(LiON)+O-57.3xx2`
`DeltaH_(ioni(LiOH)=22.5KJ//mol`.