The number of moles of`KMnO_(4)` required to oxidise 2 mol of `FeC_(2)O_(4)` is acidin medium is :-

Options

A. 1.2
B. 3.33
C. 0.4
D. 0.8

Answer

A

Explanation

`MnO_(4)^(-)+FeC_(2)O_(4)toMn^(+2)+Fe^(+3)+CO_(2)`
Equivlents of `MnO_(4)^(-)` = Equivlents of ` FeC_(2)O_(4)`
`X xx 5 = 2 xx3`
X = 1.2mol