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For decolourisation of 1.5 moles of KMnO...

For decolourisation of 1.5 moles of `KMnO_(4)` the moles of `H_(2)O_(2)` requires

A

`(3)/(2)`

B

`(9)/(4)`

C

`(15)/(4)`

D

`(21)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
Equivalents of `KMnO_(4)`=Equivalents of `H_(2)O_(2)1.5xx5=x xx2`
`x=(1.5xx5)/(2)=(15)/(4)`
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