How many grams of `I_(2)` are present in a solution which requires 40ml of 0.11 N `Na_(2)S_(2)O_(3)` to react with it :-
`I_(2)+S_(2)O_(3)^(2-)+2I^(-)`

Options

A. 12.7g
B. 0.558g
C. 12.7g
D. 0.558g

Answer

B

Explanation

Equivalents of `I_(2)` = Equivalents of `S_(2)O_(3)^(-2)`
`(X)/(254)xx2=NxxV(L)`
`(x)/(127)=(4)/(1000)xx0.11`
`x=0.558 g`