The ratio of rateof diffusion for two gases is 1 : 2 if their molecular masses :-

Options

A. `16.1`
B. `1:16`
C. `1:4`
D. `4:1`

Answer

D

Explanation

`r_(SO2)=sqrt(2)r_(x)`
`(r_(SO2))/(r_(x))=sqrt(2)=sqrt((M_(WX))/(Mwso_(2)))=sqrt((M_(WX))/(64))`
`M_(WX)=2xx64xx=128`
`V.D=(Mw)/(2)=(128)/(2)=64`