In a solid, oxide ions are arrnged in ccp, cations A occupy A occupy `(1/8)^th` of the tetrahedral voids and cation B occupy `(1/4)^(th)` of the octahedral voids. The formula of the compound is:

Options

A. `ABO_(4)`
B. `AB_(2)O_(3)`
C. `A_(2)BO_(4)`
D. `AB_(4)O_(4)`

Answer

A

Explanation

`O^(-2)to"ccp"to4`
`Ato((1)/(8))^(th) T.V.=(1)/(8)xx8=1`
`Bto((1)/(4))^(th) O.V.=(1)/(4)xx4=1`