Home
Class 12
CHEMISTRY
When AgCI is dopped with 0.01 mole CdCI(...

When AgCI is dopped with 0.01 mole `CdCI_(2)`, What is number of cationic vacancies ?

A

`0.02 N_(A)`

B

`0.01N_(A)`

C

0.01

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
B
When AgCl is dopped with `CdCI_(2)` No. of `Cd^(+2)` added = No. of cation vacancies.
Promotional Banner

Similar Questions

Explore conceptually related problems

The quantum yield for decomposition of HI id 0.2 .In an experiment 0.01 moles of HI are decomposed . Find the number of photons absorbed.

If solution sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point water (Delta T_(f)) , when 0.01 mole of solution sulphate is dissolved in 1 kg of water, is: (K'_(f) = 1.86 kg mol^(-1))

The molal boiling point constant of water is 0.573^(@)C kg "mole"^(-1) . When 0.1 mole of glucose is dissolved in 1000g of water, the solution boils under atmospheric pressure at:

Let log_(a)N=alpha + beta where alpha is integer and beta =[0,1) . Then , On the basis of above information , answer the following questions. If N_1 is number of integers when a=2 and alpha=2 and N_2 is number of integers when alpha=1 and a=3 , then the minimum value of (N_1+N_(2))