What will be the molality of solution prepared by dissolving 3.7 g propanoic acid 80 g benzene ?

Options

A. 0.77 m
B. 0.625 m
C. 0.045 m
D. 46.25 m

Answer

B

Explanation

moles of acid `=(3.7)/(74)=0.05`
molality of solution `=(w)/(m)xx(1000)/(w_(("ing")))=(0.05)/(80)xx1000`
=0.625