If the sea water is 3.5% (w/w) aqueous solution of NaCI then its molality will be:-

Options

A. 0.598 m
B. 36.27 m
C. 0.62 m
D. 0.578 m

Answer

C

Explanation

Molality `=(w)/(m)xx(1000)/(w_(("ing")))`
`=(3.5)/(58.5)xx(1000)/(96.5)=0.62m`
`[because3.5%"NaCI solution"=3.5 g "NaCI in" 96.5gH_(2)O]`